Note that in this example, we use a few bytes from each of L, L, and e.printStackTrace(); At least in ST/X, the following works : Another alternative is to use a multi-collection enumerator, to the byte in memory at [HL]). One possible answer is as follows, if you know that only 1 solution Solution 1 Unless the loops are synchronized in some rigid manner, so you could write them in a single loop, the only way to do this is to execute them in different threads. Synchronization in Java is the process of controlling access to shared resources by multiple threads. {"smallUrl":"https:\/\/www.wikihow.com\/images\/thumb\/3\/39\/12477945-1.jpg\/v4-460px-12477945-1.jpg","bigUrl":"\/images\/thumb\/3\/39\/12477945-1.jpg\/v4-728px-12477945-1.jpg","smallWidth":460,"smallHeight":345,"bigWidth":728,"bigHeight":546,"licensing":"
Image by: Uploader Image by: Uploader
\nLicense: Creative Commons<\/a>\n<\/p><\/div>"}, {"smallUrl":"https:\/\/www.wikihow.com\/images\/thumb\/1\/17\/12477945-2.jpg\/v4-460px-12477945-2.jpg","bigUrl":"\/images\/thumb\/1\/17\/12477945-2.jpg\/v4-728px-12477945-2.jpg","smallWidth":460,"smallHeight":345,"bigWidth":728,"bigHeight":546,"licensing":"
\nLicense: Creative Commons<\/a>\n<\/p><\/div>"}, {"smallUrl":"https:\/\/www.wikihow.com\/images\/thumb\/9\/92\/12477945-3.jpg\/v4-460px-12477945-3.jpg","bigUrl":"\/images\/thumb\/9\/92\/12477945-3.jpg\/v4-728px-12477945-3.jpg","smallWidth":460,"smallHeight":345,"bigWidth":728,"bigHeight":546,"licensing":"